document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1159166>Question 1159166</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A local concert center reports that it has been experiencing a 15% rate of no-shows on advanced reservations. Among 150 advanced reservations, find the probability that there will be fewer than 20 no-shows. Round the standard deviation to three decimal places to work the problem.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #782439 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=782439\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> mean is 150*0.15=22.5<BR>\n" );
document.write( "variance is np(1-p)=22.5*0.85=19.125<BR>\n" );
document.write( "sd is sqrt (V)=4.373\r<BR>\n" );
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document.write( "fewer than 20 no shows means < 19.5 using continuity correction factor<BR>\n" );
document.write( "z<(19.5-22.5)/4.373<BR>\n" );
document.write( "z<-0.686<BR>\n" );
document.write( "that probability is 0.2464\r<BR>\n" );
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document.write( "(exact is 0.2509) </SPAN>\n" );
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