document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1159168>Question 1159168</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Assume that the heights of men are normally distributed with a mean of 68.9 inches and a standard deviation of 2.8 inches. If 64 men are randomly selected, find the probability that they have a mean height greater than 68.5 inches. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #782435 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=782435\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> this probability is z>(68.5-68.9)/2.8/sqrt(64), basically the difference from the mean divided by some measure of the variance, here the std deviation/ sqrt of sample size.\r<BR>\n" );
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document.write( "z> -0.4*8/2.8<BR>\n" );
document.write( "z>-3.2/2.8  or -1.143<BR>\n" );
document.write( "that probability is 0.8735 </SPAN>\n" );
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