document.write( "Question 15879: 2log(x+3) - log(x+1) = log(2x+3) What does x equal?? \n" ); document.write( "
Algebra.Com's Answer #7824 by rapaljer(4671)\"\" \"About 
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Ir may help to rewrite the equation:\r
\n" ); document.write( "\n" ); document.write( "2log(x+3) = log(x+1) + log(2x+3)
\n" ); document.write( "\"log%28%28x%2B3%29%29%5E2+=+log+%28%28x%2B1%29%282x%2B3%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "Since log A = log B means that A=B, in the same way
\n" ); document.write( "\"log%28%28x%2B3%29%29%5E2+=+log+%28%28x%2B1%29%282x%2B3%29%29\" means that \"%28x%2B3%29%5E2+=+%28x%2B1%29%2A%282x%2B3%29+\"
\n" ); document.write( "\"x%5E2+%2B+6x+%2B9+=+2x%5E2+%2B5x+%2B+3\"
\n" ); document.write( "\"0+=+x%5E2-x-6\"
\n" ); document.write( "\"0+=+%28x-3%29%28x%2B2%29+\"
\n" ); document.write( "x= 3 or x= -2\r
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\n" ); document.write( "\n" ); document.write( "You must reject x=-2, since it gives you the log of a negative, which is not defined in the resl numbers. The final answer is x=3.\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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