document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1159218>Question 1159218</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Make the trigonometric substitution<BR>\n" );
document.write( "x = a tan θ for −π/2 < θ < π/2 and a > 0.\r<BR>\n" );
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document.write( "Simplify the resulting expression.<BR>\n" );
document.write( "x2/<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28a%5E2+%2B+x%5E2%29 ALIGN=MIDDLE  ALT=\"sqrt%28a%5E2+%2B+x%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Please help! I do not know what I am substituting nor do I know how to solve this problem.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #782386 by </B><A HREF=/tutors/aboutme.mpl?userid=MowMow><B>MowMow(42)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MowMow><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MowMow><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=782386\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^2/SQRT(a^2 + a^2Tan^2θ)<BR>\n" );
document.write( "x^2/SQRT(a^2(1+Tan^2θ)) = x^2/SQRT(a^2Sec^2(θ)) = a^2Tan^2θ /(a^2Sec^2θ)<BR>\n" );
document.write( "= aTan^2θ/Secθ = aSin^2θ(Cosθ)/Cos^2θ) = aSin^2θ/Cosθ </SPAN>\n" );
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