document.write( "Question 1159349: The posts of a hockey goal are 2.0 m apart. A player attempts to score by shooting the puck along the ice from a point 12.0 m from one post and 10.1 m from the other. Within what angle theta must the shot be made? Round your answer to the nearest degree \n" ); document.write( "
Algebra.Com's Answer #782366 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Diagram \n" ); document.write( " ![]() \n" ); document.write( "Points A and B are the goal posts \n" ); document.write( "Point C is the player's position \n" ); document.write( "Angle C = theta is the angle in which sweeps out the possible places to shoot the puck in between the goal posts\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use the law of cosines to find angle C \n" ); document.write( "c^2 = a^2 + b^2 - 2*a*b*cos(C) \n" ); document.write( "(2)^2 = (10.1)^2 + (12)^2 - 2*(10.1)*(12)*cos(C) \n" ); document.write( "4 = 102.01 + 144 - 242.4*cos(C) \n" ); document.write( "4 = 246.01 - 242.4*cos(C) \n" ); document.write( "246.01 - 242.4*cos(C) = 4 \n" ); document.write( "-242.4*cos(C) = 4-246.01 \n" ); document.write( "-242.4*cos(C) = -242.01 \n" ); document.write( "cos(C) = -242.01/(-242.4) \n" ); document.write( "cos(C) = 0.99839108910891 approximately \n" ); document.write( "C = arccos(0.99839108910891) \n" ); document.write( "C = 3.25058757974158 also approximate; make sure your calculator is in degree mode\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "When rounding to the nearest whole number, we then get C = 3 degrees\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: 3 degrees \n" ); document.write( " \n" ); document.write( " |