document.write( "Question 1159354: Prove sin^2 x cos^2 x + cos^4 x = (1-sinx) (1+sinx) is an identity \n" ); document.write( "
Algebra.Com's Answer #782365 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "Throughout this problem, I'm going to only alter the left side. The right side will stay the same the entire time.\r
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\n" ); document.write( "\n" ); document.write( "\"sin%5E2%28x%29%2Acos%5E2%28x%29+%2B+cos%5E4%28x%29+=+%281-sin%28x%29%29%281%2Bsin%28x%29%29\"\r
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\n" ); document.write( "\n" ); document.write( " Factor out the GCF cos^2(x)\r
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\n" ); document.write( "\n" ); document.write( "\"cos%5E2%28x%29%281%29+=+%281-sin%28x%29%29%281%2Bsin%28x%29%29\" Pythagorean Identity: sin^2(x) + cos^2(x) = 1\r
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\n" ); document.write( "\n" ); document.write( "\"cos%5E2%28x%29+=+%281-sin%28x%29%29%281%2Bsin%28x%29%29\" \r
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\n" ); document.write( "\n" ); document.write( "\"1-sin%5E2%28x%29+=+%281-sin%28x%29%29%281%2Bsin%28x%29%29\" Variation of the pythagorean identity\r
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\n" ); document.write( "\n" ); document.write( "\"%281-sin%28x%29%29%281%2Bsin%28x%29%29+=+%281-sin%28x%29%29%281%2Bsin%28x%29%29\" Difference of squares rule\r
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\n" ); document.write( "\n" ); document.write( "The identity has been confirmed as we get the same expression on both sides.
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