document.write( "Question 1159294: The average score of all golfers for a particular course has a mean of 75 and a standard deviation of 3.5. Suppose 49 golfers played the course today. Find the probability that the average score of the 49 golfers exceed 76. \n" ); document.write( "
Algebra.Com's Answer #782357 by Boreal(15235)\"\" \"About 
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z=(x-mean)/sd/sqrt(n)
\n" ); document.write( "z>=(76-75)/3.5/sqrt(49)
\n" ); document.write( ">=7/3.5=2
\n" ); document.write( "That probability of z>2 is 0.0228
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