document.write( "Question 1159294: The average score of all golfers for a particular course has a mean of 75 and a standard deviation of 3.5. Suppose 49 golfers played the course today. Find the probability that the average score of the 49 golfers exceed 76. \n" ); document.write( "
Algebra.Com's Answer #782357 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! z=(x-mean)/sd/sqrt(n) \n" ); document.write( "z>=(76-75)/3.5/sqrt(49) \n" ); document.write( ">=7/3.5=2 \n" ); document.write( "That probability of z>2 is 0.0228 \n" ); document.write( " |