document.write( "Question 1159337: Suppose that IQ scores in one region are normally distributed with a standard deviation of 14. Suppose also that exactly 60% of the individuals from this region have IQ scores of greater than 100(and that 40% do not).
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document.write( "What is the mean IQ score for this region? Carry your intermediate computations to at least four decimal places. Round your answer to at least one decimal place. \n" );
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Algebra.Com's Answer #782352 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! z=(x-mean)/sd \n" ); document.write( "60th percentile is a z-score of 0.2533 \n" ); document.write( "therefore, 0.2533=(100-mean)/14 \n" ); document.write( "so 3.5469=100-mean, multiplying through by 14 \n" ); document.write( "the mean = 100-3.5469=96.45 or 96.5 is the mean \n" ); document.write( " |