document.write( "Question 107351This question is from textbook precalculus
\n" ); document.write( ": the directions of the textbook say write an expression for the apparent nth term of the sequence.( assume that n begiins with 1)
\n" ); document.write( "and for 43. it has the numbers 0, 3, 8, 15, 24
\n" ); document.write( "how would you do that \n" ); document.write( "
Algebra.Com's Answer #78231 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
n=1, 0
\n" ); document.write( "n=2, 3
\n" ); document.write( "n=3, 8
\n" ); document.write( "n=4, 15
\n" ); document.write( "n=5, 24
\n" ); document.write( "If I add 1 to each output I have a perfect square.
\n" ); document.write( "The function is then is a perfect square minus 1.
\n" ); document.write( "\"f%28n%29=n%5E2-1\"
\n" ); document.write( "The other pattern is that the difference between two output numbers is a consecutive odd number.
\n" ); document.write( "\"f%28n%2B1%29-f%28n%29=%28%28n%2B1%29%5E2-1%29-%28n%5E2-1%29%29\"
\n" ); document.write( "\"f%28n%2B1%29-f%28n%29=%28%28n%5E2%2B2n%2B1-1%29-n%5E2%2B1%29\"
\n" ); document.write( "\"f%28n%2B1%29-f%28n%29=+2n%2B1\"
\n" ); document.write( "That's just interesting more than anything else.
\n" ); document.write( "Now back to the problem.
\n" ); document.write( "The expression for the nth term is then, as above,
\n" ); document.write( "\"f%28n%29=n%5E2-1\"
\n" ); document.write( "and the value for the 43rd term is then,
\n" ); document.write( "\"f%28n%29=n%5E2-1\"
\n" ); document.write( "\"f%2843%29=43%5E2-1\"
\n" ); document.write( "\"f%2843%29=1848\"
\n" ); document.write( " \n" ); document.write( "
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