document.write( "Question 355589: If A and B are independent events, P(A) = 0.4, and P(B) = 0.6, find the probabilities below.\r
\n" ); document.write( "\n" ); document.write( "(a) P(A intersection B)\r
\n" ); document.write( "\n" ); document.write( "(b) P(A union B)
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Algebra.Com's Answer #782302 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "(a) 0.24
\n" ); document.write( "(b) 0.76\r
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\n" ); document.write( "\n" ); document.write( "Work Shown\r
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\n" ); document.write( "\n" ); document.write( "Part (a)\r
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\n" ); document.write( "\n" ); document.write( "P(A intersection B) = P(A)*P(B) ... only works if A and B are independent\r
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\n" ); document.write( "\n" ); document.write( "P(A intersection B) = 0.4*0.6\r
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\n" ); document.write( "\n" ); document.write( "P(A intersection B) = 0.24\r
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\n" ); document.write( "\n" ); document.write( "Note: the other tutor seemed to have mixed up some formulas. Perhaps they were thinking about P(A union B) = P(A)+P(B). This formula only works if A and B are disjoint or mutually exclusive.\r
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\n" ); document.write( "\n" ); document.write( "Part (b)\r
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\n" ); document.write( "\n" ); document.write( "P(A union B) = P(A) + P(B) - P(A intersection B)\r
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\n" ); document.write( "\n" ); document.write( "P(A union B) = 0.4 + 0.6 - 0.24\r
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\n" ); document.write( "\n" ); document.write( "P(A union B) = 0.76
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