document.write( "Question 1159089: Your car’s speedometer is geared to accurately give your speed using a certain tire size: 15” diameter wheels (the metal part) and 4.35” tires (the rubber part).\r
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document.write( "(a) If your car's instruments are properly calibrated, how many times should your tire rotate per second if you are travelling at 55 mi/hr?
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document.write( "(b) You buy new 5.25” tires and drive at a constant speed of 60 mph (according to your car’s instrument). However, a cop stops you and claims that you were speeding. How fast did the radar gun clock you moving?
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document.write( "(c) Then you replace your tires with 3.6” tires. When your speedometer reads 25 mph, how fast are you really moving?
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Algebra.Com's Answer #782252 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! 55 mi/hr is 80.6667 ft/sec \n" ); document.write( "C=pi*d \n" ); document.write( "if the diameter is 23.70 inches (2 rubber parts and the wheel), then the circumference of the tire is 74.45 inches or 6.205 feet \n" ); document.write( "That would make 13.00 rev/sec for 55 mph or 60/55 *13=14.18 rev/sec at 60 mph\r \n" ); document.write( "\n" ); document.write( "5.25 inch tires have a diameter of 25.5 inches and a circumference of 80.11 inches or 6.676 feet \n" ); document.write( "At 14.18 rev/sec, one is now going 94.678 ft/sec or 64.55 mph or 65 mph rounded\r \n" ); document.write( "\n" ); document.write( "3.6 inch tires now have a diameter 22.2 inches or 69.74 inches circumference or 5.812 feet \n" ); document.write( "13 rev/sec for 55 mph or 5.909 rev/sec for 25 mph \n" ); document.write( "with these new tires, 5.812*5.909 is 34.34 ft/sec or 23.42 mph \n" ); document.write( " \n" ); document.write( " |