document.write( "Question 1159250: Write an equation of a line that passes through the point (-1,2) and is perpendicular to the line y=1/2x-3. \n" ); document.write( "
Algebra.Com's Answer #782231 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "a line that passes through the point (\"-1\",\"2\") and is \"perpendicular\" to the line \r
\n" ); document.write( "\n" ); document.write( "\"y=%281%2F2%29x-3\"-> slope is \"m=1%2F2\"\r
\n" ); document.write( "\n" ); document.write( "perpendicular line will have a slope negative reciprocal to \"m=1%2F2\"\r
\n" ); document.write( "\n" ); document.write( "it is \"m=-1%2F%281%2F2%29=-2\"\r
\n" ); document.write( "\n" ); document.write( "use point slope formula:\r
\n" ); document.write( "\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where m is a slope \"-2\", \"x%5B1%5D\" and \"y%5B1%5D\" coordinates of given point (\"-1\",\"2\")\r
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\n" ); document.write( "\n" ); document.write( "\"y-2=-2%28x-%28-1%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"y-2=-2%28x%2B1%29\"\r
\n" ); document.write( "\n" ); document.write( "\"y-2=-2x-2\"\r
\n" ); document.write( "\n" ); document.write( "\"y=-2x-2%2B2\"\r
\n" ); document.write( "\n" ); document.write( "\"y=-2x\"-> your equation\r
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