document.write( "Question 107350This question is from textbook intermediate algebra
\n" ); document.write( ": Through (-2,4) and (5,0).
\n" ); document.write( "find an equation of each line in standard form satisfying the given conditions.
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Algebra.Com's Answer #78221 by Annabelle1(69)\"\" \"About 
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we need to find the gradient between these two points first. This is found by the formula
\n" ); document.write( "\"%28y2-y1%29%2F%28x2-x1%29\"
\n" ); document.write( "where x1,x2,y1,y2 are your coordinates.\r
\n" ); document.write( "\n" ); document.write( "(-2,4)=(x1,y1)
\n" ); document.write( "(5,0)=(x2,y2)\r
\n" ); document.write( "\n" ); document.write( "so x1=-2 x2=5 y1=4 y2=0\r
\n" ); document.write( "\n" ); document.write( "gradient(m)= \"%280-4%29%2F%285-%28-2%29%29\"
\n" ); document.write( "=\"-4%2F7\"\r
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\n" ); document.write( "\n" ); document.write( "you then have to use your point gradient formula to find the equation of the line.: (y-y1)=m*(x-x1)\r
\n" ); document.write( "\n" ); document.write( "you can use the x1 and y1 from above\r
\n" ); document.write( "\n" ); document.write( "we have :
\n" ); document.write( "\"y-4=%28-4%2F7%29%2A%28x-%28-2%29%29\"
\n" ); document.write( "\"y-4=%28-4%2F7%29%2A%28x%2B2%29\"
\n" ); document.write( "\"7%28y-4%29=-4%2A%28x%2B2%29\"
\n" ); document.write( "\"7y-28=-4x-8\"
\n" ); document.write( "\"4x%2B7y-28%2B8=0\"
\n" ); document.write( "\"4x%2B7y-20=0\"
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