document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=15868>Question 15868</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the hypotenuse of a right triangle measures 13 feet and one measures 5 feet. find the lenght of the other leg? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #7822 by </B><A HREF=/tutors/aboutme.mpl?userid=vasu2qute><B>vasu2qute(17)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vasu2qute><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=7822\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hypotenuse = 13ft<BR>\n" );
document.write( "Length of one leg = 5ft <BR>\n" );
document.write( "Let length of other leg be x ft <BR>\n" );
document.write( "According to Pythogora's Theorem <BR>\n" );
document.write( "     Side^2 + Side^2 = Hypotenuse^2<BR>\n" );
document.write( "        5^2 + x^2 = 13^2<BR>\n" );
document.write( "         25 +x^2  = 169<BR>\n" );
document.write( "             x^2 =169 - 25<BR>\n" );
document.write( "                 = 144<BR>\n" );
document.write( "              x= 12 ft<BR>\n" );
document.write( "There fore the length of the other leg = 12 ft </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );