document.write( "Question 107446: Draw a rough sketch of the following function. Use your basic shapes and shifting. \r
\n" ); document.write( "\n" ); document.write( "f(x)= (square root of) x-4
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Algebra.Com's Answer #78217 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\"f%28x%29=+sqrt%28x+-+4%29\"\r
\n" ); document.write( "\n" ); document.write( "We can find for what \"x\" is \"+sqrt%28x+-+4%29+=+0\", and we will see that for f, it'll be \"x+%3E=4\", because any \"x%3C4\" will give us the square root of a negative number which is undefined.\r
\n" ); document.write( "\n" ); document.write( " \"f%28x%29\" is defined for all real \"x\" excluding \"4\",
\n" ); document.write( "or from (\"-+infinity\" to\"4\"] and from[\"4\" to \"infinity\") \r
\n" ); document.write( "\n" ); document.write( "to solve this,
\n" ); document.write( "\"sqrt%28x+-+4%29+=+0\" raise both sides of an equation to a second power\r
\n" ); document.write( "\n" ); document.write( "\"%28sqrt%28x+-+4%29%29%5E2+=+0%5E2\"
\n" ); document.write( "\"x+-+4+=+0\"
\n" ); document.write( "\"x++=++4\"\r
\n" ); document.write( "\n" ); document.write( "to sketch it, you will need at least two points because the graph will be a line (it is linear function):\r
\n" ); document.write( "\n" ); document.write( "\"x+\" | \"+f%28x%29\"
\n" ); document.write( "\"0+\" | \"+-4\"
\n" ); document.write( "\"4+\" | \"+0\"\r
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\n" ); document.write( "\n" ); document.write( "here is the graph:\r
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Solved by pluggable solver: Graphing Linear Equations
In order to graph \"y=1%2Ax-4\" we only need to plug in two points to draw the line
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\n" ); document.write( " So lets plug in some points
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\n" ); document.write( " Plug in x=-5
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\n" ); document.write( " \"y=1%2A%28-5%29-4\"
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\n" ); document.write( " \"y=-5-4\" Multiply
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\n" ); document.write( " \"y=-9\" Add
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\n" ); document.write( " So here's one point (-5,-9)
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\n" ); document.write( " Now lets find another point
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\n" ); document.write( " Plug in x=-4
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\n" ); document.write( " \"y=1%2A%28-4%29-4\"
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\n" ); document.write( " \"y=-4-4\" Multiply
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\n" ); document.write( " \"y=-8\" Add
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\n" ); document.write( " So here's another point (-4,-8). Add this to our graph
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\n" ); document.write( " Now draw a line through these points
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\n" ); document.write( " So this is the graph of \"y=1%2Ax-4\" through the points (-5,-9) and (-4,-8)
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\n" ); document.write( " So from the graph we can see that the slope is \"1%2F1\" (which tells us that in order to go from point to point we have to start at one point and go up 1 units and to the right 1 units to get to the next point) the y-intercept is (0,\"-4\")and the x-intercept is (\"4\",0)
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\n" ); document.write( " We could graph this equation another way. Since \"b=-4\" this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0,\"-4\").
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\n" ); document.write( " So we have one point (0,\"-4\")
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\n" ); document.write( " Now since the slope is \"1%2F1\", this means that in order to go from point to point we can use the slope to do so. So starting at (0,\"-4\"), we can go up 1 units
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\n" ); document.write( " and to the right 1 units to get to our next point
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\n" ); document.write( " Now draw a line through those points to graph \"y=1%2Ax-4\"
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\n" ); document.write( " So this is the graph of \"y=1%2Ax-4\" through the points (0,-4) and (1,-3)
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