document.write( "Question 1159172: A river has a current speed of 5 miles per hour. A boat travels down river for 20 miles. It then makes the return trip up the river. If the return trip took 8 hours and 20 minutes longer than the trip down river, what is the speed of the boat in still water? \n" ); document.write( "
Algebra.Com's Answer #782169 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "If r is the speed in mph of the boat in still water, then its upstream speed is r-5 and its downstream speed is r+5.

\n" ); document.write( "upstream time: 20/(r-5)
\n" ); document.write( "downstream time: 20/(r+5)

\n" ); document.write( "The upstream time is 8 1/3 hours (25/3 hours) greater than the downstream time:

\n" ); document.write( "\"20%2F%28r-5%29+=+20%2F%28r%2B5%29%2B25%2F3\"
\n" ); document.write( "Multiply everything by the least common denominator, 3(r-5)(r+5):

\n" ); document.write( "\"60%28r%2B5%29+=+60%28r-5%29%2B25%28r%5E2-25%29\"
\n" ); document.write( "\"60r%2B300+=+60r-300%2B25r%5E2-625\"
\n" ); document.write( "\"1225+=+25r%5E2\"
\n" ); document.write( "\"r%5E2+=+49\"
\n" ); document.write( "\"r+=+7\" (clearly the r = -7 solution makes no sense...)

\n" ); document.write( "ANSWER: The speed of the boat in still water is 7mph

\n" ); document.write( "CHECK:
\n" ); document.write( "upstream speed: 20/(7-5) = 20/2 = 10
\n" ); document.write( "downstream speed: 20/(7+5) = 20/12 = 5/3 = 1 2/3
\n" ); document.write( "10 - 1 2/3 = 8 1/3

\n" ); document.write( "
\n" ); document.write( "
\n" );