document.write( "Question 1159156: The point (-6, -8) is on the terminal arm of an angle 𝜽 in standard position.
\n" ); document.write( "What is the correct ratio for sin𝜽, cos𝜽, tan𝜽? \n" ); document.write( "

Algebra.Com's Answer #782153 by MathLover1(20850) $\"\"$ $\"About$

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The point ( $\"-6\"$ , $\"-8\"$ )-> angle $\"theta\"$ is in quadrant $\"+III\"$ \r
\n" ); document.write( "\n" ); document.write( "draw the triangle in that quad, the hypotenuse would be \r
\n" ); document.write( "\n" ); document.write( " $\"hypotenuse=sqrt%28%28-6%29%5E2%2B%28-8%29%5E2%29=sqrt%2836%2B64%29=sqrt%28100%29=10\"$ \r
\n" ); document.write( "\n" ); document.write( "Note in this case $\"theta+=+180+%2B+reference-angle%28alpha%29\"$
\n" ); document.write( " $\"sin%28alpha%29=-8%2F10=-4%2F5\"$ -> $\"-53.13\"$ °
\n" ); document.write( " $\"cos%28alpha%29=-6%2F10=-3%2F5\"$ -> $\"126.9\"$ °
\n" ); document.write( " $\"+tan%28alpha%29=-8%2F-6=4%2F3\"$ -> $\"53.13\"$ °\r
\n" ); document.write( "\n" ); document.write( " Note:\r
\n" ); document.write( "\n" ); document.write( " $\"+-sin+%28alpha%29+=+sin%28+theta%29\"$
\n" ); document.write( " $\"+-cos%28+alpha+%29=+cos+%28theta%29+\"$
\n" ); document.write( " $\"+tan%28+alpha%29+=+tan+%28theta%29\"$ \r
\n" ); document.write( "\n" ); document.write( " that is, the sin and cos are $\"negative\"$ in the third quadrant and the tan is positive\r
\n" ); document.write( "\n" ); document.write( " $\"+tan%28+alpha%29=53.13\"$ °, then\r
\n" ); document.write( "\n" ); document.write( " $\"theta+=+180+%2B+53.13=233.13\"$ ° is angle in quadrant $\"+III\"$ \r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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