document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1159125>Question 1159125</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find how long it takes $1000 investment to earn $100 interest if it is invested at 8% interest compounded quarterly. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #782117 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=782117\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1100=1000(1+0.08/4)^4n, n is number of years<BR>\n" );
document.write( "1.1=1.02^4n<BR>\n" );
document.write( "logs both sides<BR>\n" );
document.write( "log 1.1=4n log 1.02<BR>\n" );
document.write( "divide<BR>\n" );
document.write( "log 1.1/log 1.02=4.813=4n<BR>\n" );
document.write( "n=1.2 years\r<BR>\n" );
document.write( "\n" );
document.write( "rough check--makes $80 the first year and that *1.2=$96, and compounding itself will make it $100. </SPAN>\n" );
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