document.write( "Question 1159087: A bacteria culture initially contains 1500 bacteria and doubles every half hour.\r
\n" );
document.write( "\n" );
document.write( "Find the size of the baterial population after 100 minutes.
\n" );
document.write( " \r
\n" );
document.write( "\n" );
document.write( "Find the size of the baterial population after 4 hours. \n" );
document.write( "
Algebra.Com's Answer #782072 by josgarithmetic(39618)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "p, initial size \n" ); document.write( "x, number of HOURS passed\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If p is 1500 then \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "100 minutes is 60 minutes plus 40 minutes, or \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " |