document.write( "Question 1159087: A bacteria culture initially contains 1500 bacteria and doubles every half hour.\r
\n" ); document.write( "\n" ); document.write( "Find the size of the baterial population after 100 minutes.
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\n" ); document.write( "\n" ); document.write( "Find the size of the baterial population after 4 hours.
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Algebra.Com's Answer #782072 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
\"y=p%2A2%5E%282x%29\"
\n" ); document.write( "p, initial size
\n" ); document.write( "x, number of HOURS passed\r
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\n" ); document.write( "\n" ); document.write( "If p is 1500 then \"y=15002%5E%282x%29\".\r
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\n" ); document.write( "\n" ); document.write( "100 minutes is 60 minutes plus 40 minutes, or \"1%262%2F3\" hours.
\n" ); document.write( "\"y=1500%2A2%5E%282%28cross%285%2F2%29%29%29\"
\n" ); document.write( "\"y=1500%2A2%5E%282%285%2F3%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"y=1500%2A2%5Ecross%285%29\"
\n" ); document.write( "\"y=1500%2A2%5E%2810%2F3%29\"\r
\n" ); document.write( "\n" ); document.write( "\"y=15120\" after 100 minutes
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