document.write( "Question 1158944: A bank loaned out $13,500, part of it at the rate of 9% annual interest, and the rest at 13% annual interest. The total interest earned for both loans was $1,635.00. How much was loaned at each rate? \n" ); document.write( "
Algebra.Com's Answer #782070 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Here is a non-algebraic alternative for solving \"mixture\" problems like this.

\n" ); document.write( "$13,500 all at 9% would yield $1215 interest.
\n" ); document.write( "$13,500 all at 3% would yield $1755 interest.
\n" ); document.write( "The actual interest was $1635.

\n" ); document.write( "On a number line (if you want to think of it that way), 1635 is 420/540 = 7/9 of the way from 1215 to 1755.

\n" ); document.write( "Therefore, 7/9 of the total was invested at 13% (and the other 2/9 of it at 9%).

\n" ); document.write( "2/9 of $13,500 is $3000; 7/9 is $10,500.

\n" ); document.write( "ANSWER: $10,500 at 13%; $3000 at 9%.

\n" ); document.write( "CHECK:
\n" ); document.write( ".13(10,500)+.09(3000) = 1365+270 = 1635

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