document.write( "Question 1159033: a farmer needs to enclose a rectangular field with a fence down the middle to divide it into two equal parts. The material for the divider down the middle cost $50 per foot ant the material for the outside cost $20 per foot. He wants the area of the field to be 1600 sq/ft. what dimensions will minimize the cost of material\r
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Algebra.Com's Answer #782002 by ikleyn(52782) $\"\"$ $\"About$

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document.write( "From the context, the dimensions of the rectangle are not given for advance - they are unknowns and they should be found\r\n" );
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document.write( "from the minimum cost condition.\r\n" );
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document.write( "Let x be one dimension and y be the other dimension of the rectangle.\r\n" );
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document.write( "Then the cost of the outside perimeter fence is 20*(2x+2y) dollars = 40*(x+y) dollars,\r\n" );
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document.write( "while the cost of the fence down middle is 50*x dollars.\r\n" );
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document.write( "The total cost of the fence is  \r\n" );
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document.write( "    C(x,y) = 40x + 40y + 50x = 90x + 40y  dollars.      ANSWER\r\n" );
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document.write( "It shoud be minimized under the restriction\r\n" );
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document.write( "    x*y = 1600  square feet.\r\n" );
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\n" ); document.write( "\n" ); document.write( "The problem's question is just answered; thus the problem's solution is completed.\r
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\n" ); document.write( "\n" ); document.write( "For a TWIN problem, the full solution, including minimization part, is in the lesson\r
\n" ); document.write( "\n" ); document.write( " - Calculus optimization problems for shapes in 2D plane, Problem 5\r
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