document.write( "Question 1158998: What is the radius of the largest circle that will fit inside a triangle that has two 15-inch
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Algebra.Com's Answer #781984 by ikleyn(52781)\"\" \"About 
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document.write( "The given triangle is isosceles with congruent lateral sides of 15 inches long\r\n" );
document.write( "and the base of 18 inches.\r\n" );
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document.write( "The altitude of this triangle drawn to the 18-inches side, divide this triangle in two right-angled triangles.\r\n" );
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document.write( "This altitude is one leg of these triangles, while the other legs are 18/2 = 9 inches long.\r\n" );
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document.write( "From the Pythagorean theorem, the length of the altitude is  \"sqrt%2815%5E2-9%5E2%29\" = 12 inches.\r\n" );
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document.write( "Then the area of the given triangle is  \"%281%2F2%29%2A18%2A12%29\" = 9*12 = 108 sq.inches.\r\n" );
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document.write( "Let the radius of the inscribed circle be r.\r\n" );
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document.write( "Now use the formula  \r\n" );
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document.write( "    area = \"%281%2F2%29%2AP%2Ar\"\r\n" );
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document.write( "for the triangle, where P is the perimeter P of the triangle   P = 15+15+12 = 42 inches.\r\n" );
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document.write( "The area of the triangle is 108 sq.inches.\r\n" );
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document.write( "Hence,  108 = \"%281%2F2%29%2A42%2Ar\",  which gives\r\n" );
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document.write( "    r = \"%282%2A108%29%2F42\" = \"%282%2A6%2A18%29%2F42\" = \"%282%2A18%29%2F7\" = \"36%2F7\" inches.   ANSWER\r\n" );
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