document.write( "Question 1157956: A midwestern city had a population of 650,000 in 2010. The population, which follows the exponential model, decreased 4.65% per year. Show all work!\r
\n" ); document.write( "\n" ); document.write( " a. Find the exponential function that models the population after t years.
\n" ); document.write( " (Remember to change the rate to a negative decimal.)\r
\n" ); document.write( "\n" ); document.write( " b. What is the projected population in the year 2020?\r
\n" ); document.write( "\n" ); document.write( " c. In how many years will the population be expected to be 300,000?
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Algebra.Com's Answer #781981 by Amily_2190(27)\"\" \"About 
You can put this solution on YOUR website!
a)Population decreased 4.65% per year; -4.65%= -.0465
\n" ); document.write( "To determine how much of the population remains per year, subtract 4.65%(-.0465) from the total population of 100% or 1.
\n" ); document.write( "1-.0465=.9535
\n" ); document.write( "t=# of years after 2010\r
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\n" ); document.write( "\n" ); document.write( "Answer: P(t)= 650,000(.9535)^t \r
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\n" ); document.write( "\n" ); document.write( "b) 2020-2010= 10 (2020 is 10 years after 2010, so t=10)
\n" ); document.write( "P(t)=650,000(.9535)^10 is approximately 403,757\r
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\n" ); document.write( "\n" ); document.write( "c) 300,000= 650,000(.9535)^t
\n" ); document.write( "300,000/650,000=(.9535)^t
\n" ); document.write( "(Use logarithm to figure out t on calculator)
\n" ); document.write( "log base .9535 of 300,000/650,000 equals t\r
\n" ); document.write( "\n" ); document.write( "\"log+.9535%28300000%2F650000%29=t\"
\n" ); document.write( "t is approximately 16.2 years
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