document.write( "Question 1158967: Find the fifth term of the sequence. \r
\n" );
document.write( "\n" );
document.write( "a(n) = 4a[(sub)n-1]+3, a(1) = 3\r
\n" );
document.write( "\n" );
document.write( "(n-1) is in subscript after 4a. I hope that makes sense. I tried using some of the formulas that I was given in class and can't seem to find one that works for me. Thank you so much in advance. <3 \n" );
document.write( "
Algebra.Com's Answer #781968 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Follow the pattern to calculate the remaining two terms you need. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " ![]() \n" ); document.write( " |