document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1158917>Question 1158917</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The TV chef was mixing a 5 ounce sauce containing 50% tangy mustard with another sauce containng 75% tangy mustard to get a sauce containing 70% tangy mustard.  How many ounces of the 75% tangy mustard sauce must the chef have used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #781900 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=781900\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5 oz*.50 tangy =2.50 oz-tangy<BR>\n" );
document.write( "add x oz of 0.75 tangy or +0.75x<BR>\n" );
document.write( "final is (5+x)*0.7=3.5+0.7x<BR>\n" );
document.write( "so 2.50+0.75x=3.5+0.7x<BR>\n" );
document.write( "0.05x=1<BR>\n" );
document.write( "x=20 oz of 75% tangy ANSWER\r<BR>\n" );
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document.write( "start with  5 ounces or 2.5 o-t<BR>\n" );
document.write( "add to that 20 ounces or 15 o-t<BR>\n" );
document.write( "end up with 25 oz of 0.7 or 17.5 o-t so this  checks </SPAN>\n" );
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