document.write( "Question 1158898: You just got a free ticket for a boat ride, and you can bring along 4 friends! Unfortunately, you have 6 friends who want to come along.
\n" ); document.write( "How many different groups of friends could you take with you? \n" ); document.write( "

Algebra.Com's Answer #781882 by solver91311(24713) $\"\"$ $\"About$

You can put this solution on YOUR website!
\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "If you have 6 friends, there are 6 ways to choose the first person who comes with you. For each of those 6, there are 5 ways to choose the second person. Hence there are 6 X 5 = 30 ways to choose the first two. Then, for each of those 30 ways to choose the first two, there are 4 ways to choose the third person...and so on.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "

\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "John
\n" ); document.write( "

\n" ); document.write( "My calculator said it, I believe it, that settles it
\n" ); document.write( "

\n" ); document.write( "

\n" );