document.write( "Question 1158897: when lyn and john were married 21 years ago, john was three times as old as lyn. Today he is twice as old as she. How old was helen on her wedding day. \n" ); document.write( "

Algebra.Com's Answer #781880 by josgarithmetic(39620) $\"\"$ $\"About$

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Who is Helen? She was not part of the description.\r
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\n" ); document.write( "\n" ); document.write( "y, John
\n" ); document.write( "x, Lyn
\n" ); document.write( " $\"system%28y-21=3%28x-21%29%2Cy=2x%29\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"2x-21=3%28x-21%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"2x-21=3x-63\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"63-21=x\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x=42\"$ -------------Lyn, now
\n" ); document.write( "-
\n" ); document.write( " $\"y=84\"$ -----------John now\r
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\n" ); document.write( "\n" ); document.write( "You can just subtract 21 from each to see age of each when they were married twentyone years ago. \n" ); document.write( "

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