document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1158795>Question 1158795</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 5 pencils and 4 crayons are 19.6 inches. 6 pencils and 5 crayons are 23.8 inches. Each pencil is the same length as the other pencils, and each crayon is the same length as the other crayons. What is the length of 1 pencil? What is the length of 1 crayon? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #781832 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13206)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=781832\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The difference between the two measurements is 1 more pencil and 1 more crayon for 4.2 more inches.<br><BR>\n" );
document.write( "So the length of 4 pencils and 4 crayons is 4(4.2) = 16.8 inches.<br><BR>\n" );
document.write( "Then comparing that to 5 pencils and 4 crayons with a total lengths of 19.6 inches, we find the length of 1 pencil is 19.6-16.8 = 2.8 inches.<br><BR>\n" );
document.write( "And then the length of one crayon is 4.2-2.8 = 1.4 inches.<br><BR>\n" );
document.write( "That common sense solution is equivalent to one of many possible solutions using formal algebra:<br><PRE STYLE=\"white-space: pre-wrap; white-space: -moz-pre-wrap; white-space: -pre-wrap; white-space: -o-pre-wrap; word-wrap: break-word;\">\r\n" );
document.write( "(1)  5p+4c = 19.6    (given)\r\n" );
document.write( "(2)  6p+5c = 23.8    (given)\r\n" );
document.write( "(3)  p+c = 4.2       (2)-(1)\r\n" );
document.write( "(4)  4p+4c = 16.8    4*(3)\r\n" );
document.write( "(5)  p = 2.8         (1)-(4)\r\n" );
document.write( "(6)  c = 1.4         (3)-(5)</PRE><BR>\n" );
document.write( " </SPAN>\n" );
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