document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1158770>Question 1158770</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Investment Problem<BR>\n" );
document.write( "A man invested Php 6,000, part of it at 3% and the rest at 4%. The total annual income from the<BR>\n" );
document.write( "two investments is Php 208. How much is invested at each of these rates? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #781782 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=781782\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "An alternative to the standard algebraic solution method which, in this example, makes the calculations very simple....<br><BR>\n" );
document.write( "All 6000 at 3% would yield 180 interest; all at 4% would yield 240 interest.<br><BR>\n" );
document.write( "Find where the actual interest of 208 lies between 180 and 240:<BR>\n" );
document.write( "240-180 = 60; 208-180 = 28<BR>\n" );
document.write( "208 is 28/60 of the way from 180 to 240<br><BR>\n" );
document.write( "That means 28/60 of the total was invested at the higher rate.<br><BR>\n" );
document.write( "28/60 of the total 6000 is 2800.<br><BR>\n" );
document.write( "ANSWER: 2800 at 4%; the remaining 3200 at 3%.<br><BR>\n" );
document.write( "CHECK: .04(2800)+.03(3200) = 112+96 = 208<br><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );