document.write( "Question 1158484: A sample of 68 college students yields a mean annual income of $3248 and a standard deviation of $885. Find the margin of error in estimating μ at the 99% level of confidence? \n" ); document.write( "
Algebra.Com's Answer #781767 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! margin of error is t(0.995 df=67)*s/sqrt(n) \n" ); document.write( "t=2.65 \n" ); document.write( "the margin of error is 2.65*885/sqrt(68)=$284.40 \n" ); document.write( " |