document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1158747>Question 1158747</A>: <I><SPAN STYLE=\"word-break: break-all;\"> On​ Monday, Harold picked up six donuts and two large coffees for the office staff.  He paid $ 5.94 .  On​ Tuesday, Melinda picked up four donuts and five large coffees for the office staff.  She paid $ 7.04 .  What is the cost of one​ donut?  What is the cost of one large​ coffee? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #781764 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=781764\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6D+2C=5.94; so 12D+4C=11.88<BR>\n" );
document.write( "4D+5C=7.04; so -12D-15C=-21.12 multiplying by -3<BR>\n" );
document.write( "-11C=-9.24, adding the two<BR>\n" );
document.write( "C=$0.84<BR>\n" );
document.write( "therefore 6D+1.68=5.94, so 6D=$4.26 and D=$0.71<BR>\n" );
document.write( "check in second\r<BR>\n" );
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document.write( "4(0.71)+5(0.84)=$7.04<BR>\n" );
document.write( "coffee is $0.84 and donut is $0.71\r<BR>\n" );
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document.write( " </SPAN>\n" );
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