document.write( "Question 1158755: An actor invests some money at 9%, and $32000 more than twice the amount at 12%. The total annual interest earned from the investment is $23640. How much did he invest at each amount? \n" ); document.write( "

Algebra.Com's Answer #781754 by VFBundy(438) $\"\"$ $\"About$

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9% investment:
\n" ); document.write( "Principal = p
\n" ); document.write( "Rate = 0.09
\n" ); document.write( "Interest = 0.09p
\n" ); document.write( "
\n" ); document.write( "12% investment:
\n" ); document.write( "Principal = 2p + 32000
\n" ); document.write( "Rate = 0.12
\n" ); document.write( "Interest = 0.12(2p + 32000) = 0.24p + 3840
\n" ); document.write( "
\n" ); document.write( "0.09p + (0.24p + 3840) = 23640
\n" ); document.write( "
\n" ); document.write( "0.33p = 19800
\n" ); document.write( "
\n" ); document.write( "p = 60000
\n" ); document.write( "
\n" ); document.write( "9% investment:
\n" ); document.write( "Principal = p = $60,000
\n" ); document.write( "
\n" ); document.write( "12% investment:
\n" ); document.write( "Principal = 2p + 32000 = 2(60000) + 32000 = 120000 + 32000 = $152,000 \n" ); document.write( "

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