document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=107404>Question 107404</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the sides of a square are decreased by 2 cm, the area is decreased by<BR>\n" );
document.write( "36 cm2. What were the dimensions of the original square? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #78174 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=78174\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (X-2)^2=X^2-36<BR>\n" );
document.write( "X^2-4X+4=X^2-36<BR>\n" );
document.write( "-4X=-36-4<BR>\n" );
document.write( "-4X=-40<BR>\n" );
document.write( "X=-40/-4<BR>\n" );
document.write( "X=10 CM ANSWER FOR THE ORIGINAL DIMENSIONS OF THE SQUARE.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "(10-2)^2=10^2-36<BR>\n" );
document.write( "8^2=100-36<BR>\n" );
document.write( "64=64<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );