document.write( "Question 1158757: An actor invested some money at 9% simple interest,and $42,000 more than four times the amount at 10%. The total annual interest earned from the investment was $43,890. How much did he invest at each amount? \n" ); document.write( "

Algebra.Com's Answer #781739 by ikleyn(52835) $\"\"$ $\"About$

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document.write( "Let x be the amount invested at 9%; then the amount invested at 10% is (x+42000).\r\n" );
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document.write( "The interest from the 9% investment is  0.09x.\r\n" );
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document.write( "The interest of the 10% investment is  0.10*(x+42000).\r\n" );
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document.write( "The total investment equation is  \r\n" );
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document.write( "    0.09x + 0.10*(x+42000) = 43890.\r\n" );
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document.write( "From the equation\r\n" );
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document.write( "    x =  = 208894.74.\r\n" );
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document.write( "ANSWER.  $208894.74 invested at 9%;  208894.74 + 42000 = 250894.74 dollars invested at 10%.\r\n" );
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document.write( "CHECK.   0.09*208894.74 + 0.10*250894.74 = 43890 dollars.  Correct.\r\n" );
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