document.write( "Question 1158750: When a plane flies with the​ wind, it can travel 840 miles in 2 hours. When the plane flies in the opposite​ direction, against the​ wind, it takes 5 hours to fly the same distance. Find the rate of the plane in still air and the rate of the wind. \n" ); document.write( "
Algebra.Com's Answer #781730 by VFBundy(438)\"\" \"About 
You can put this solution on YOUR website!
With the wind:
\n" ); document.write( "Distance = 840
\n" ); document.write( "Rate = d/t = 420
\n" ); document.write( "Time = 2
\n" ); document.write( "
\n" ); document.write( "Against the wind:
\n" ); document.write( "Distance = 840
\n" ); document.write( "Rate = d/t = 168
\n" ); document.write( "Time = 5
\n" ); document.write( "
\n" ); document.write( "Let s = rate in still air
\n" ); document.write( "Let w = speed of wind
\n" ); document.write( "
\n" ); document.write( "s + w = 420
\n" ); document.write( "s - w = 168
\n" ); document.write( "
\n" ); document.write( "2s = 588
\n" ); document.write( "
\n" ); document.write( "s = 294
\n" ); document.write( "
\n" ); document.write( "If s = 294, and s + w = 420, then w = 126
\n" ); document.write( "
\n" ); document.write( "s = rate in still air = 294
\n" ); document.write( "w = speed of wind = 126
\n" ); document.write( "
\n" );