document.write( "Question 1158750: When a plane flies with the wind, it can travel 840 miles in 2 hours. When the plane flies in the opposite direction, against the wind, it takes 5 hours to fly the same distance. Find the rate of the plane in still air and the rate of the wind. \n" ); document.write( "
Algebra.Com's Answer #781730 by VFBundy(438)![]() ![]() You can put this solution on YOUR website! With the wind: \n" ); document.write( "Distance = 840 \n" ); document.write( "Rate = d/t = 420 \n" ); document.write( "Time = 2 \n" ); document.write( " \n" ); document.write( "Against the wind: \n" ); document.write( "Distance = 840 \n" ); document.write( "Rate = d/t = 168 \n" ); document.write( "Time = 5 \n" ); document.write( " \n" ); document.write( "Let s = rate in still air \n" ); document.write( "Let w = speed of wind \n" ); document.write( " \n" ); document.write( "s + w = 420 \n" ); document.write( "s - w = 168 \n" ); document.write( " \n" ); document.write( "2s = 588 \n" ); document.write( " \n" ); document.write( "s = 294 \n" ); document.write( " \n" ); document.write( "If s = 294, and s + w = 420, then w = 126 \n" ); document.write( " \n" ); document.write( "s = rate in still air = 294 \n" ); document.write( "w = speed of wind = 126 |