document.write( "Question 1158713: A lab technician needs 35 mL of 15% base solution for a certain experiment, but she has only 10% solution and 20% solution. How many milliliters of the 10% and the 20% solutions should she mix to get what she needs?
\n" ); document.write( "The technician will need mL of the 10% solution and mL of 20% solution \n" ); document.write( "

Algebra.Com's Answer #781697 by greenestamps(13203) $\"\"$ $\"About$

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\n" ); document.write( "Common sense should tell us that, since 15% is halfway between 10% and 20%, the mixture should use equal amounts of the 10% and 20% solutions.

\n" ); document.write( "ANSWER: 17.5 mL of each

\n" ); document.write( "Algebraically, if required....

\n" ); document.write( "x = mL of 10% solution
\n" ); document.write( "35-x = mL of 20% solution

\n" ); document.write( "The total amount in the two ingredients is 15% of the total 35 mL:

\n" ); document.write( " $\".10%28x%29%2B.20%2835-x%29+=+.15%2835%29\"$

\n" ); document.write( "Solve using basic algebra; of course your answer should be 17.5 mL of each.

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