document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=107393>Question 107393</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the area of the trapezoid<BR>\n" );
document.write( "bases are 8 & 4 inches.  Non Parallel sides are 5 and 7 inches and height is 7 inches.  <BR>\n" );
document.write( "Perimeter is 24 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #78169 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=78169\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> BREAKING THIS TRAP INTO 2 FIGURES OF  RECTANGLE & A TRIANGLE WE HAVE:<BR>\n" );
document.write( "THERECTANGLE FROM THE MIDDLE IS:<BR>\n" );
document.write( "HEIGHT OF 7 & LENGTH OF 4 OR 7*4=28 SQ. INCHES.<BR>\n" );
document.write( "NOTE THAT ONE OF THE NON PARALLEL SIDES IS 7 INCHES THE SAME AS THE HEIGHT.<BR>\n" );
document.write( "THAT LEAVES THE REMAINING 4 INCHES OF THE LONGER BASE AS THE BASE FOR THE REMAINING TRIANGLE.<BR>\n" );
document.write( "WHAT IS LEFT OF ONE END IS A RIGHT TRIANGLE OF HEIGHT = 7 BASE =4 & SIDE OF 5:<BR>\n" );
document.write( "THIS AREA=4/2*7=2*7=14 SQ. INCHES.<BR>\n" );
document.write( "NOW WE ADD THESE 2 AREAS & WE GET 28+14=42 SQ INCHES. </SPAN>\n" );
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