document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1158683>Question 1158683</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The maintenance department at the main campus of a large state university receives daily requests to replace fluorecent lightbulbs. The distribution of the number of daily requests is bell-shaped and has a mean of 49 and a standard deviation of 9. Using the 68-95-99.7 rule, what is the approximate percentage of lightbulb replacement requests numbering between 49 and 58?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #781682 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=781682\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 49 is the mean and 58 is 1 sd above the mean.<BR>\n" );
document.write( "If 68% of all requests are between +/- 1 sd, then half or 34% are between 0 and +1 sd. <BR>\n" );
document.write( "34% is the approximate percentage. </SPAN>\n" );
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