document.write( "Question 1158671: A man is four times older than his son but five years older than his wife. The sum of their ages is 103. How old is the man? \n" ); document.write( "

Algebra.Com's Answer #781642 by Shin123(626) $\"\"$ $\"About$

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Let the man's age be $\"x\"$ . His son's age is $\"x%2F4\"$ and his wife's age is $\"x-5\"$ . So we have the equation $\"x%2Bx%2F4%2B%28x-5%29=103\"$ . Simplifying, we get $\"9x%2F4=108\"$ . Multiplying both sides by 4, we get $\"9x=432\"$ . Dividing both sides by 9 gives $\"highlight%28highlight_green%28highlight%28x=48%29%29%29\"$ . Check, $\"48%2B48%2F4%2B%2848-5%29=48%2B12%2B43=60%2B43=highlight%28103%29\"$ . \n" ); document.write( "

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