document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1158645>Question 1158645</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the range,  standard deviation, and variance show your solution <BR>\n" );
document.write( "A survey of 10 fast-food restaurant noted the number of calories in a mid-sized hamburger.  The following are the results <BR>\n" );
document.write( "514 507 502 498 496 506 458 478 463 514 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #781625 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=781625\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> add them up and divide by 10, the mean is 493.6<BR>\n" );
document.write( "The range is high - low or 514-458 or 56<BR>\n" );
document.write( "the variance is the average of the squared deviations from the mean\r<BR>\n" );
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document.write( "the standard deviation first required taking the squared deviations from the mean and dividing by n, if it is a population, or n-1, if it is a sample, which this is. Then take the square root of that result.<BR>\n" );
document.write( "s=20.3<BR>\n" );
document.write( "the terms are 20.4^2+13.4^2+8.4^2+4.4^2+2.4^2+12.4^2+35.6^2+15.6^2+30.6^2+20.4^2=412.04, variance<BR>\n" );
document.write( "sd is sqrt (412.04)=20.30\r<BR>\n" );
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document.write( " </SPAN>\n" );
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