document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1158657>Question 1158657</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The time needed to make a photo enlargement varies jointly as its length and width. If it takes 12 seconds to make a 4\" by 6\" enlargement, how many seconds does it take to make one that is 8\" by 10\"? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #781601 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=781601\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> T=kLW<BR>\n" );
document.write( "12=k*6*4=24k<BR>\n" );
document.write( "k=1/2\r<BR>\n" );
document.write( "\n" );
document.write( "use k below<BR>\n" );
document.write( "T=0.5*10*8<BR>\n" );
document.write( "T=40 seconds </SPAN>\n" );
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