document.write( "Question 107377: A bus leaves a station at 1 pm traveling west at an average rate of 44 miles per hour. One hour later a second bus leaves the same station, traveling east at an rate of 48 miles per hour. At what time will the two buses be 274 miles apart? \n" ); document.write( "
Algebra.Com's Answer #78159 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A bus leaves a station at 1 pm traveling west at an average rate of 44 miles per hour. One hour later a second bus leaves the same station, traveling east at an rate of 48 miles per hour. At what time will the two buses be 274 miles apart? \n" ); document.write( ": \n" ); document.write( "Let t = travel time of the westbound bus when they are 274 mi apart \n" ); document.write( "Then \n" ); document.write( "(t-1) = travel time of the eastbound bus when they are 274 mi apart \n" ); document.write( ": \n" ); document.write( "Write a distance equation: Distance = speed * time \n" ); document.write( ": \n" ); document.write( "West bus dist + East bus dist = 274 mi \n" ); document.write( "44t + 48(t-1) = 274 \n" ); document.write( "44t + 48t - 48 = 274 \n" ); document.write( "92t = 274 + 48 \n" ); document.write( "92t = 322 \n" ); document.write( "t = 322/92 \n" ); document.write( "t = 3.5 hrs is the travel time of the west bound bus \n" ); document.write( "Then we know: \n" ); document.write( "2.5 hrs is the travel time of the east bound bus \n" ); document.write( ": \n" ); document.write( "Find the time: \n" ); document.write( "1:00 + 3:30 = 4:30 PM, time they will be 274 mi apart \n" ); document.write( ": \n" ); document.write( "Check solution by finding the sum of the distances: \n" ); document.write( "44(3.5) + 48(2.5) = \n" ); document.write( "154 + 120 = 274 mi as given \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Did this make sense to you? Any questions? \n" ); document.write( " |