document.write( "Question 1158613: different amounts are invested at 10%, 11%, and 12% yearly interest. the amount invested at 11% is $300 more than the amount invested at 10% and the total yearly income from all 3 investments is $324. a total of $2900 is invested. find the amount invested at each rate. \n" ); document.write( "

Algebra.Com's Answer #781586 by MathTherapy(10552) $\"\"$ $\"About$

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\n" ); document.write( "different amounts are invested at 10%, 11%, and 12% yearly interest. the amount invested at 11% is $300 more than the amount invested at 10% and the total yearly income from all 3 investments is $324. a total of $2900 is invested. find the amount invested at each rate.
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I would implore you NOT to even pay attention or look at the other person's attempt to help you. Numerous times on here these people have been SHOWN how to do these
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document.write( "problems and STOP making them so COMPLEX and time-consuming but they NEVER learn! Maybe they consider themselves too old to learn or maybe they're just STUBBORN!
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document.write( "Anyway, this is how this should be done.\r
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document.write( "Let the amount invested at 10% be T
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document.write( "Then the amount invested at 11% is, T + 300
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document.write( "And so, amount invested at 12% = 2,900 - (T + T + 300) = 2,900 - 2T - 300 = 2,600 - 2T
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document.write( "We now get: .1T + .11(T + 300) + .12(2,600 - 2T) = 324
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document.write( ".1T + .11T + 33 + 312 - .24T = 324
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document.write( ".1T + .11T - .24T = 324 - 345
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document.write( "- .03T = - 21
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document.write( "Amount invested at 10%, or 
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document.write( "You should now be able to determine the amounts invested at the other rates.
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document.write( "That's IT!! Nothing as COMPLEX and TIME-CONSUMING as one of the NOVELISTS makes it seem!! \n" );
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