document.write( "Question 1158609: I am a rectangular picture frame.if I were straight.I would be 120 inches long.I am wrapped around a picture.and my length is twice as long as my width.what is the area of the picture that I am wrapped around. \n" ); document.write( "
Algebra.Com's Answer #781556 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "I am a rectangular picture frame.if I were straight.I would be 120 inches long.\r
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\n" ); document.write( "\n" ); document.write( "=> perimeter is \r
\n" ); document.write( "\n" ); document.write( "\"P=2%28L%2BW%29=120in\"........eq.1\r
\n" ); document.write( "\n" ); document.write( "I am wrapped around a picture and my length is twice as long as my width\r
\n" ); document.write( "\n" ); document.write( "\"L=2W\".......eq.2\r
\n" ); document.write( "\n" ); document.write( "first find dimensions:\r
\n" ); document.write( "\n" ); document.write( "\"2%28L%2BW%29=120in\"\r
\n" ); document.write( "\n" ); document.write( "\"L%2BW=60in\"........substitute in \"L=2W\"\r
\n" ); document.write( "\n" ); document.write( "\"2W%2BW=60in\"\r
\n" ); document.write( "\n" ); document.write( "\"3W=60in\"\r
\n" ); document.write( "\n" ); document.write( " \"W=20in\"\r
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\n" ); document.write( "\n" ); document.write( "substitute back in \"L=2W\"\r
\n" ); document.write( "\n" ); document.write( "\"L=2%2A20in\"\r
\n" ); document.write( "\n" ); document.write( "\"L=40in\"\r
\n" ); document.write( "\n" ); document.write( " the area of the picture that I am wrapped around is:\r
\n" ); document.write( "\n" ); document.write( "\"A=L%2AW\"\r
\n" ); document.write( "\n" ); document.write( "\"A=40in%2A20in\"\r
\n" ); document.write( "\n" ); document.write( "\"A=800in%5E2\"\r
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