document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1158568>Question 1158568</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ed and Hew are product testers at IL Incorp.  Ed can drop a piece of luggage off the top of headquarters and then record the results once every 4 minutes.  Hew can do the same once every 5 minutes.  How many minutes will it take them together to drop their luggage and record the results a (combined)total of 18 times? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #781540 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13203)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=781540\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Consider the least common multiple of the two given times, which is 20 minutes.<br><BR>\n" );
document.write( "In 20 minutes, Ed can drop 20/4=5 pieces of luggage and Hew can drop 20/5=4 pieces of luggage.  So in 20 minutes together, the two of them can drop 5+4=9 pieces of luggage.<br><BR>\n" );
document.write( "18 pieces is twice that number; so it will take them twice as long -- 40 minutes -- to drop 18 pieces of luggage.<br><BR>\n" );
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