document.write( "Question 1158503: Suppose you record the time spent for lunch for seven days and the results are: 10, 13, 15, 13, 16, 21, and 18 minutes. If the population (all days) is normally distributed, construct a 98% confidence interval for the population mean. \n" ); document.write( "
Algebra.Com's Answer #781534 by Boreal(15235)\"\" \"About 
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98%CI is mean +/-t(0.99, df=6)*s/sqrt(n)
\n" ); document.write( "15.14 is mean, s=3.63, n=7
\n" ); document.write( "t=3.143
\n" ); document.write( "interval half width is 4.31 (margin of error)
\n" ); document.write( "(10.83, 19.45)
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