document.write( "Question 1158503: Suppose you record the time spent for lunch for seven days and the results are: 10, 13, 15, 13, 16, 21, and 18 minutes. If the population (all days) is normally distributed, construct a 98% confidence interval for the population mean. \n" ); document.write( "
Algebra.Com's Answer #781534 by Boreal(15235) You can put this solution on YOUR website! 98%CI is mean +/-t(0.99, df=6)*s/sqrt(n) \n" ); document.write( "15.14 is mean, s=3.63, n=7 \n" ); document.write( "t=3.143 \n" ); document.write( "interval half width is 4.31 (margin of error) \n" ); document.write( "(10.83, 19.45) \n" ); document.write( " \n" ); document.write( " |