document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1158562>Question 1158562</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Billy and Kendall each drove to their grandmother’s house from their house.  Billy left one<BR>\n" );
document.write( "hour before Kendall.  Billy drove at a rate of 45 mph.  Kendall drove at a rate of 60 mph. How long will it take for Kendall to catch up to Billy?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #781528 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=781528\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "In the hour that Billy drove at 45mph before Kendall started, Billy drove 45 miles.<br><BR>\n" );
document.write( "Once Kendall started driving at 60mph, the rate at which he caught up to Billy was 60-45 = 15mph.<br><BR>\n" );
document.write( "To make up the 45 miles at a rate of 15 miles per hour will take 45/15 = 3 hours.<br><BR>\n" );
document.write( "If you need an algebraic solution....<br><BR>\n" );
document.write( "When Kendall caught up to Billy, Kendall had driven x hours at 60mph and Billy had driven (x+1) hours at 45mph:<br><BR>\n" );
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document.write( "Solve using basic algebra.<br><BR>\n" );
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