document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1158552>Question 1158552</A>: <I><SPAN STYLE=\"word-break: break-all;\"> It is known that 1.3% of all car tires produced in a tire factory is defected. Suppose you randomly select 60 car tires for inspection. What is the probability that more than 1.5% of the 60 car tires is defected? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #781503 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=781503\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This would be 1 or more tires, since 1.5% of 60 is 0.9.<BR>\n" );
document.write( "that means first get the probability 60 tires are all not defective and subtract that from 1. The result would be all with defects 1,2,...<BR>\n" );
document.write( "0.987^60=0.4561 is probability all aren't and 0.5439 is probability at least one is. </SPAN>\n" );
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