document.write( "Question 1158529: [If we] Should work with three digit numbers divisible by three, what would be
\n" ); document.write( "the initial and final value of the counting variable?
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #781475 by Edwin McCravy(20055) $\"\"$ $\"About$

You can put this solution on YOUR website!
[If we] Should work with three digit numbers divisible by three, what would be
\n" ); document.write( "the initial and final value of the counting variable?
\n" ); document.write( "

\r\n" );
document.write( "The smallest and largest three digit numbers, respectively, are 100 and 999.\r\n" );
document.write( "\r\n" );
document.write( "We divide each by 3\r\n" );
document.write( "\r\n" );
document.write( "   33         333\r\n" );
document.write( "3)100       3)999\r\n" );
document.write( "   9          9\r\n" );
document.write( "   10          9 \r\n" );
document.write( "    9          9 \r\n" );
document.write( "    1           9\r\n" );
document.write( "                9\r\n" );
document.write( "                0\r\n" );
document.write( "\r\n" );
document.write( "100 leaves a remainder, so we increase 33 to the next integer, 34 and multiply\r\n" );
document.write( "that by 3 and get 102, so that's the initial three digit number divisible by 3.\r\n" );
document.write( "Since 999 did not leave a remainder, it's divisible by 3, so it's the final\r\n" );
document.write( "value of the counting variable.\r\n" );
document.write( "\r\n" );
document.write( "Answers: 102 and 999\r\n" );
document.write( "  \r\n" );
document.write( "Edwin

\n" ); document.write( "

\n" );