document.write( "Question 11901: I am trying to figure out how to simplify and hence solve the following equation.\r
\n" ); document.write( "\n" ); document.write( "\"log%28x%2C+5%29+%2B+log%285%2C+x%29+=+2\"
\n" ); document.write( "I know \"log%28b%2C+x%29=1%2Flog%28x%2C+b%29\" but I am stuck as I don't know how to deal with \"1%2Flog%28x%2C+5%29\" other than to make it \"%28log%28x%2C+5%29%29%5E-1\" but then what do you do with that? Perhaps I am going about it the wrong way. Any help would be appreciated, thankyou.
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Algebra.Com's Answer #7814 by khwang(438)\"\" \"About 
You can put this solution on YOUR website!
\"log%28x%2C+5%29+%2B+log%285%2C+x%29+=+2\"
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\n" ); document.write( " Let \"y++=+log%285%2C+x%29\",then we have y + 1/y = 2,\r
\n" ); document.write( "\n" ); document.write( " so \"y%5E2-+2y+%2B+1+=+0+\"\r
\n" ); document.write( "\n" ); document.write( " Hence, y = 1 and then x = \"5%5Ey+\" ???\r
\n" ); document.write( "\n" ); document.write( " It is very staightford, I think you can understand.\r
\n" ); document.write( "\n" ); document.write( " Kenny
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